如何通过定义点arrow
在方程上绘制?Tikz
这是一个起始代码。
\documentclass[a4paper]{book}
\usepackage{tikz}
\begin{document}
\begin{tikzpicture}
\node at (0,0) {$93 \stackrel{12}{\equiv} - 27 \Rightarrow 93 \stackrel{12}{\equiv} \underbrace{-27 + \overbrace{3 \times 12}}_{9} \Rightarrow 93 \stackrel{12}{\equiv} 9$};
\draw[->] (-.75,.5) -- (-.75,1) -- (1,1) -- (1,.75);
\end{tikzpicture}
\end{document}
3
最佳答案
2
像这样吗?
\documentclass[a4paper]{book}
\usepackage{tikz}
\usetikzlibrary{tikzmark}
\begin{document}
\begin{tikzpicture}[remember picture,overlay]
\node at (0,0) {$93 \stackrel{12}{\equiv} - 27 \Rightarrow 93 \stackrel{\subnode{a}{12}}{\equiv} \underbrace{-27 + \subnode{b}{\overbrace{3 \times 12}}}_{9} \Rightarrow 93 \stackrel{12}{\equiv} 9$};
\draw [->] (a.north) -- ++(0pt,5mm) -| (b.north);
\end{tikzpicture}
\end{document}
|
\documentclass[a4paper]{book}
\usepackage[x11names]{xcolor}
\usepackage{amsmath}
\usepackage{tikz}
% BEGIN_FOLD
\usetikzlibrary{tikzmark}
\usetikzlibrary{arrows.meta}
% default arrow type
\tikzset{
>={Triangle[width=1ex, length=1.5ex]}
}
% END_FOLD
\begin{document}
\begin{tikzpicture}[remember picture,inner sep=0pt,outer sep=0pt]
\node at (0,0) {
$93 \stackrel{12}{\equiv} - 27 \Rightarrow 93 \mspace{\thinmuskip}
\tikzmarknode{name1}{\stackrel{12}{\mathrel{\equiv}}}
\mspace{\thinmuskip} \underbrace{-27 +
\tikzmarknode{name2}{\overbrace{3 \times 12}}_{9}}
\Rightarrow 93 \stackrel{12}{\equiv} 9$
};
\draw[thick,color=DodgerBlue3,->] (name1.north) -- ([yshift=1.5em] name1.north) -- ([yshift=1.5em] name1.north -| name2.north) -- (name2.north);
\end{tikzpicture}
\end{document}
1
-
将 放入
\tikzmarknode
tikzpicture 中会涉及嵌套 tikzpictures,这可能会带来问题。该\subnode
命令就是为此目的而编写的。
–
|
tikzmark
?–
–
–
|